-5=2b^2-11b+10

Solution for -5=2b^2-11b+10 equation:

-5=2b^2-11b+10

We move all terms to the left:

-5-(2b^2-11b+10)=0

We get rid of parentheses

-2b^2+11b-10-5=0

We add all the numbers together, and all the variables

-2b^2+11b-15=0

a = -2; b = 11; c = -15;
Δ = b2-4ac
Δ = 112-4·(-2)·(-15)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-1}{2*-2}=\frac{-12}{-4}
=+3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+1}{2*-2}=\frac{-10}{-4}
=2+1/2
$